- #1
Isma
- 27
- 0
can some 1 help me with it pleasezz
How can that be an answer when there was no "a" in the original question?Isma said:just kno the answer but don't kno anything else
ans: 2ay''+y'(raise to the power 3)=0
Vaishakh said:2ay + y^3 = 0.
2a = -y^2
This represents a circle!
Isma said:yesss!
thx a lot :)
A differential equation is a mathematical equation that describes how a variable changes over time in terms of its rate of change. It involves derivatives, which are measures of how a function changes when its input changes.
A circle passing through the origin can be represented by the differential equation x^2 + y^2 = r^2, where r is the radius of the circle and x and y are the coordinates of any point on the circle.
No, a circle passing through the origin has only one solution. This is because the circle is defined by a fixed radius and any point that satisfies the equation x^2 + y^2 = r^2 will lie on the circle passing through the origin.
Differential equations for circles passing through the origin can be used to model the motion of planets around the sun, the orbit of satellites around the earth, or the movement of a pendulum in a circular motion.
Yes, there are specific techniques for solving differential equations for circles passing through the origin, such as using polar coordinates or the separation of variables method. These techniques take into consideration the circular nature of the equation and make the solving process more efficient.