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Differentail Eq. For circle passing through origin

  1. Feb 16, 2006 #1
    can some 1 help me with it plzzz
  2. jcsd
  3. Feb 16, 2006 #2

    Tom Mattson

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    can u post the qstn plzzz? :biggrin:
  4. Feb 16, 2006 #3
    question is find the differential eq. for circle that passes through origin.
  5. Feb 16, 2006 #4

    Tom Mattson

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    That can't be all there is to it. There are an infinite number of circles that pass through the origin.
  6. Feb 16, 2006 #5
    exactly....i m v confused....thats all wat the question is for assignment i ve to submit tomorrow
    i just kno the answer but dont kno anything else
    ans: 2ay''+y'(raise to the power 3)=0
  7. Feb 16, 2006 #6
    2ay + y^3 = 0.
    2a = -y^2
    This represents a circle!!!!
  8. Feb 17, 2006 #7
    thx a lot :)
  9. Feb 17, 2006 #8
    but how will we come to this eq. from start if we dint know the DE?
  10. Feb 17, 2006 #9
    what is the eq you were given for circle that pass in (0,0) ? is it like this one : [tex](x-a)^2 +(y-b)^2 = a^2 +b^2[/tex]
    Last edited: Feb 17, 2006
  11. Feb 17, 2006 #10


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    How about writing out the entire problem as it was given?
    How can that be an answer when there was no "a" in the original question?

    In what sense does that represent a circle?

    Did you understand what he meant??

    Any circle, that passes through the origin can be written
    (x- a)2+ (y- b)2= a2+ b2
    (I just noticed that ziad1985 said that!)

    Differentiating wrt x, 2(x-a)+ 2(y-b)y'= 0.

    Differentiating again, 2+ 2y'2+ 2(y-b)y"= 0.

    Now combine those into an equation that does not have either a or b in it.
  12. Feb 19, 2006 #11
    actually....this assignment was given just after 1st lecture on DE in class...so i was v much messed up in mind....nd abt that thx heheheh....it made sense at that moment but not in the next 1:)
    i really appreciate u helpin me ...i m gonna solve it like that
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