Differentiability of functions defined on manifolds

Click For Summary
SUMMARY

The discussion centers on the differentiability of functions defined on manifolds, specifically stating that a function f defined on a manifold M with values in a Banach space is differentiable if and only if it is differentiable as a map of manifolds. The concept of differentiability as a map of manifolds is clarified through the use of homeomorphisms, where a map \Phi:M→X is differentiable at a point x in M if the composition \Phi∘a-1 is differentiable. This highlights the relationship between manifold differentiability and the structure of Banach spaces.

PREREQUISITES
  • Understanding of differentiable maps between Banach spaces
  • Familiarity with manifolds and their properties
  • Knowledge of homeomorphisms and their role in topology
  • Basic concepts of functional analysis, particularly Banach spaces
NEXT STEPS
  • Study the properties of differentiable maps in the context of Banach spaces
  • Explore the concept of homeomorphisms in manifold theory
  • Learn about the implications of differentiability in functional analysis
  • Investigate examples of differentiable functions on specific manifolds
USEFUL FOR

Mathematicians, particularly those specializing in differential geometry and functional analysis, as well as students studying advanced calculus and topology.

yifli
Messages
68
Reaction score
0
Quoted from a book I'm reading:

if f is any function defined on a manifold M with values in Banach space, then f is differentiable if and only if it is differentiable as a map of manifolds.

what does it mean by 'differentiable as a map of manifolds'?
 
Physics news on Phys.org
Hi yifli! :smile:


(I assume that you have defined what a differentiable map is between Banach spaces).

Differentiability as a map of manifolds means:

Let [itex]\Phi:M\rightarrow X[/itex] be your map from M to a Banach space. And let [itex]x\in M[/itex], then x has an open neighbourhood which is homeomorphic to an open set of [itex]\mathbb{R}^n[/itex]. Thus there exists a homeomorphism [itex]a:U\rightarrow V[/itex] with U an open set in M that contaisn x and V open in [itex]\mathbb{R}^n[/itex].

Now, [itex]\Phi[/itex] is differentiable in x if and only if [itex]\Phi\circ a^{-1}[/itex] is differentiable.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 73 ·
3
Replies
73
Views
9K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K