Differentiable Greatest Integer Function

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Homework Help Overview

The discussion revolves around the differentiability of the function k(x) defined as k(x)=x²*[1/x] for 0

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the differentiability of k(x) across its domain, questioning the implications of the function being defined in terms of the greatest integer function. There is an exploration of the behavior of the function when 1/x equals an integer and its continuity at those points.

Discussion Status

The discussion is ongoing, with participants providing insights into the differentiability of the function and questioning the reasoning behind discontinuities. There is a focus on the behavior of the function at x=0 and the potential for one-sided derivatives.

Contextual Notes

Participants note the importance of defining the function at x=0 and the implications of the greatest integer function on differentiability. There is an acknowledgment of the need for rigorous justification regarding continuity and differentiability at critical points.

kolley
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Homework Statement


k(x)=x2*[1/x] for 0<x≤1
k(x)=0 for x=0
Find where k(x) is differentiable and find the derivative

Homework Equations


The Attempt at a Solution


I know that it is differentiable for all ℝ\Z on (0,1], but I am unsure how to find the derivative for this problem.
 
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kolley said:

Homework Statement


k(x)=x2*[1/x] for 0<x≤1
k(x)=0 for x=0
Find where k(x) is differentiable and find the derivative

Homework Equations





The Attempt at a Solution


I know that it is differentiable for all ℝ\Z on (0,1], but I am unsure how to find the derivative for this problem.

If you mean what R\Z usually means then R\Z on (0,1] is (0,1). I suspect you mean something else. Suppose 1/x is between two integers, say n<1/x<n+1?
 
Yes sorry that was a typo, should be (0,1). So would I set k=[1/x], which would make f(x)=x2*k

which would imply that f'(x)=2xk
Is this what you mean?
 
kolley said:
Yes sorry that was a typo, should be (0,1). So would I set k=[1/x], which would make f(x)=x2*k

which would imply that f'(x)=2xk
Is this what you mean?

Sure. So if 1/x is between two integers then your function is differentiable, yes? Suppose 1/x is equal to an integer? Then what?
 
If it's equal to an integer then it would not be differentiable.
 
kolley said:
If it's equal to an integer then it would not be differentiable.

Why not? You have to give reasons.
 
Because it's discontinuous at all integers.
 
kolley said:
Because it's discontinuous at all integers.

True if you mean f(x) is discontinuous when 1/x is an integer. You should probably say that in a more proofy way, like saying what the one sided limits are of f(x) or using a theorem. But I think the main point of the exercise is what happens at x=0, since they bothered to define f(0)=0. f(x) might have a one-sided derivative at x=0. Does it?
 
Last edited:

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