- #1
cse63146
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Homework Statement
Find the general solution of
y' = [tex] - \frac{x}{y} - \sqrt{(\frac{x}{y})^2 + 1}[/tex]
Homework Equations
The Attempt at a Solution
I let y = ux -> y' + xu' + u
xu' + u = - u - [tex]\sqrt{u^2+1}[/tex]
u' = [tex]\frac{-2u - \sqrt{u^2 + 1}}{x}[/tex]
[tex]\frac{du}{-2u - \sqrt{u^2 + 1}} = \frac{dx}{x}[/tex]
now I'm supposed to integrate both sides, just not sure how to find the integral of [tex]\frac{du}{-2u - \sqrt{u^2 + 1}}[/tex]