Differential Equation, Change of variables

  • Thread starter binbagsss
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  • #1
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Homework Statement


Hi,

I am looking at this question:

question.jpg


With this (part of ) solution:

solution.jpg


Homework Equations




The Attempt at a Solution



I follow up to the last line-

I do not understand here how we have simply taken the ##1/t^{\alpha m + \alpha}## outside of the derivative ##\frac{\partial}{\partial y} ## since ##y=y(r,t^{\beta}) ## i.e. ##t## and ##y## are not independent variables.... ##\frac{\partial}{\partial t}= \frac{\partial y}{\partial t^{\beta}}\frac{\partial t^{\beta}}{\partial t}##

Many thanks in advance
 

Answers and Replies

  • #2
haruspex
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My problems with the algebra start before that.
A partial derivative expresses the consequences of changing one variable while one or more other variables are held constant. The full notation specifies what is held constant. E.g. if f=f(x,y) then we may write ##\frac {\partial f}{\partial x}\Big\rvert_{y=y_0}##. Nearly always, it is obvious what the 'other' variables are, and we don't need to specify their values, so we omit the vertical bar and its subscript.
In the present case, I have no idea what is being held constant as y varies.
 

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