Compute the general solution of y'' + 4y' + 20y =e-2tsin4t
The Attempt at a Solution
after using determinants, I found the [tex]\lambda_1 = -2 + 4i[/tex] and [tex]\lambda_2 = -2 - 4i[/tex]
So the general solution would be y(t) = k1e-2tcos4t + k2e-2tsin4t + yim
to find yim, would I make it equal to Ae-2te4it, find first and second derivative, and plug them in the original equation and then apply euler's method?