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Differential equation: dy/dx = e^(8x-3y), y(0)=16

  1. Feb 12, 2013 #1
    1. The next differential equation I'm working on is this:

    dy/dx= e8x - 3y

    Alright, I thought to cancel out the e, we could take the ln of both sides...?

    ln(dy/dx) = 8x-3y

    Is this right so far? It doesn't seem like it's right because... well, how can you have an ln(dy/dx)??

    Would you please help me with this part?
    Thank you very much! :)
  2. jcsd
  3. Feb 12, 2013 #2


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    You can have ln(dy/dx) but there's not much you can do with it. Use e^(a+b)=e^a*e^b to separate the equation.
  4. Feb 12, 2013 #3


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    This relationship will help a lot

    ea+b = ea*eb
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