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## Homework Statement

Solve the following IVP:

[tex]\frac{dy}{dt} = \frac{1}{2y+3}[/tex] y(0) = 1

## Homework Equations

## The Attempt at a Solution

[tex]\frac{dy}{dt} = \frac{1}{2y+3}[/tex]

[tex]\Rightarrow \int 2y + 3 dy= \int dt[/tex]

[tex]\Rightarrow y^2 + 3y= t +c[/tex] where C is a constant

Kinda stuck now. Any hints?