Differential Equation - Inverse Laplace Transformation

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SUMMARY

The inverse Laplace transformation of the function \(\frac{2s^2 + 3s - 2}{s(s+1)(s-2)}\) is correctly computed as \(1 - e^{-t} + 2e^{2t}\). The initial confusion arose from a typographical error where \(\mathcal{L}^{-1}[\frac{1}{2}]\) was mentioned instead of \(\mathcal{L}^{-1}[\frac{1}{s}]\). For additional practice problems, a resource was recommended: Ogata Chapter 2 Examples Practice.

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Homework Statement



Find the inverse laplace transformation of [tex]\frac{2s^2 +3s - 2}{s(s+1)(s-2)}[/tex]

Homework Equations





The Attempt at a Solution



[tex]L^{-1} \frac{2s^2 +3s - 2}{s(s+1)(s-2)} = L^{-1}\frac{1}{2} + L^{-1}\frac{1}{s+1} +2 L^{-1}\frac{1}{s-2} = 1 - e^{-t} + 2e^{2t}[/tex]

Have I made a mistake somewhere?

and does anyone know where I can find a website practice problems (preferably with answers so I can check) similar to this one?
 
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cse63146 said:

Homework Statement



Find the inverse laplace transformation of [tex]\frac{2s^2 +3s - 2}{s(s+1)(s-2)}[/tex]

Homework Equations





The Attempt at a Solution



[tex]L^{-1} \frac{2s^2 +3s - 2}{s(s+1)(s-2)} = L^{-1}\frac{1}{2} + L^{-1}\frac{1}{s+1} +2 L^{-1}\frac{1}{s-2} = 1 - e^{-t} + 2e^{2t}[/tex]

Have I made a mistake somewhere?

and does anyone know where I can find a website practice problems (preferably with answers so I can check) similar to this one?

Assuming that the [itex]\mathcal{L}^{-1}[\frac{1}{2}][/itex] was just a typo, and you meant to write [itex]\mathcal{L}^{-1}[\frac{1}{s}][/itex], then yes, you are correct.

As for practice problems and solutions, a quick Google search came up with http://ece.olin.edu/dynamics/handouts/ogata_ch2_examples_practice.pdf . I haven't checked the contents for correctness, but there are several worked problems in there (and I'm sure you can find more yopurself with Google!).
 
Last edited by a moderator:
Yea, I meant to write 1/s.

Thanks for the link.
 

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