Differential equation nonzero value problem

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SUMMARY

The discussion focuses on solving the differential equation y" + 9y = 0 using the function y = sin(kt). The key finding is that nonzero values of k must satisfy the condition derived from substituting y = sin(kt) into the differential equation. Additionally, it is confirmed that the family of functions y = A*sin(kt) + B*cos(kt) also serves as solutions for the same values of k, reinforcing the relationship between the sine and cosine functions in this context.

PREREQUISITES
  • Understanding of differential equations, specifically second-order linear homogeneous equations.
  • Knowledge of trigonometric functions and their derivatives.
  • Familiarity with the method of solving differential equations by substitution.
  • Ability to manipulate and simplify mathematical expressions.
NEXT STEPS
  • Study the general solution of second-order linear homogeneous differential equations.
  • Learn about the characteristic equation and its role in determining solutions.
  • Explore the implications of initial conditions on the solutions of differential equations.
  • Investigate the relationship between sine and cosine functions in the context of differential equations.
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Students studying differential equations, mathematics educators, and anyone interested in the application of trigonometric functions in solving differential equations.

Gauss177
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Homework Statement


a) For what nonzero values of k does the function y = sin kt satisfy the differential equation y" + 9y = 0?

b) For those values of k, verify that every member of the family of functions y = A*sin kt + B*cos kt is also a solution.

Homework Equations




The Attempt at a Solution


I'm a little confused on what I need to do here. I can do problems where you have to show that every member of a family of functions is a solution of a differential equation (differentiate the function, then plug in the function into the differential equation, and see if they are the same). But I don't see how to use that in this problem.

Thanks for the help.
 
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Well, why not try differentiating the function, and plugging it into the equation. This will give you a condition for k such that y=sinkt is a solution.
 

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