# Differential Equation Root of Pt (aka xy)

1. Jun 14, 2010

### avant_t7

1. The problem statement, all variables and given/known data
dP/dt=root of (Pt)

2. Relevant equations
P(1)=2

3. The attempt at a solution
Well, I figure that the integrating factor is 1, since there is no P(x) value, so it's a matter of finding the integral of root(Pt). I can't solve this because the only method I know is substitution, and it doesn't work on this equation.

Thanks guys

2. Jun 14, 2010

### Staff: Mentor

this equation is separable. Write sqrt(Pt) as P1/2t1/2.

3. Jun 14, 2010

### avant_t7

I see that, I guess I'm just confused by finding the integral of two variables. If I substitute u for Pt, and du=(t)dP/dt + P dt...

will that work?

4. Jun 14, 2010

### Staff: Mentor

You don't need to do a substitution and you aren't going to have any integrals with two variables.

$$\frac{dP}{dt} = \sqrt{Pt} = P^{1/2}t^{1/2}$$

Separate to get the following.
$$\frac{dP}{P^{1/2}} = t^{1/2} dt$$

Now integrate.

5. Jun 14, 2010

### avant_t7

shesh you're right, how silly of me.

THanks a lot Mark!