Differential equation with sphere

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SUMMARY

The discussion centers on the evaporation of a spherical mothball with an original radius of 1.2 cm, which reduces to 1 cm over 180 days. The rate of evaporation, represented by the differential equation -dr/dt = c1 * 4πr², is proportional to the sphere's surface area. The user initially calculated the time for the radius to shrink to 25% of its original size as 2694 years and the time for the volume to halve as 233.82 years, which were incorrect due to a unit conversion error. The correct calculations, once adjusted to days, yield accurate results.

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  • Understanding of differential equations
  • Knowledge of surface area calculations for spheres
  • Familiarity with initial value problems
  • Basic skills in unit conversion
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  • Study the method of separation of variables in differential equations
  • Learn about the physical principles behind evaporation rates
  • Explore the relationship between surface area and volume in geometric shapes
  • Practice unit conversion techniques in mathematical problems
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Students studying calculus, particularly those focusing on differential equations, as well as educators and anyone interested in the physical applications of mathematics in real-world scenarios.

dinospamoni
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Homework Statement



A spherical mothball of original radius 1.2 cm slowly
evaporates such that 180 days later, its radius is only 1 cm.
Physically, the rate of evaporation dr/dt is proportional to the
surface area of the sphere. Determine a) the time required for
the radius of a new mothball to shrink to 25 percent of its
original radius, and b) the time required for the volume of a
new mothball to become half of its original value.

Homework Equations



SA= 4 pi r^2
r(0)=1.2
r(180)=1

The Attempt at a Solution



I started by saying -dr/dt = c1 4 pi r^2

where c1 is a constant of proportionality

Then through separation of variables I found that

1/r = 4 pi c1 t + c2

after imposing the initial conditions I found c1=7.383*10^-5 and c2=.833

so I have

1/r = 4 pi (7.383*10^-5) t + .833

and this gives me answers of
1) 2694 yr
2) 233.82 yr

but these aren't right. Any ideas of where I went wrong?
 
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Your equation give the right values for t=0 and t=180, so I think you have some calculation error in the final steps.

I seriously doubt that mothballs evaporate like that. It would mean that evaporation is proportional to the square of the surface area.
 
Yeah, I think I might have the wrong initial equation, but I'm not sure of what it could be
 
dinospamoni said:

Homework Statement



A spherical mothball of original radius 1.2 cm slowly
evaporates such that 180 days later, its radius is only 1 cm.
Physically, the rate of evaporation dr/dt is proportional to the
surface area of the sphere. Determine a) the time required for
the radius of a new mothball to shrink to 25 percent of its
original radius, and b) the time required for the volume of a
new mothball to become half of its original value.

Homework Equations



SA= 4 pi r^2
r(0)=1.2
r(180)=1

The Attempt at a Solution



I started by saying -dr/dt = c1 4 pi r^2

where c1 is a constant of proportionality

Then through separation of variables I found that

1/r = 4 pi c1 t + c2

after imposing the initial conditions I found c1=7.383*10^-5 and c2=.833

so I have

1/r = 4 pi (7.383*10^-5) t + .833

and this gives me answers of
1) 2694 yr
2) 233.82 yr

but these aren't right. Any ideas of where I went wrong?

1/r = 4 pi (7.383*10^-5) t + .833 looks ok. Why are you giving the times in yrs? Don't you mean days? And I'd check those again.
 
Dick said:
1/r = 4 pi (7.383*10^-5) t + .833 looks ok. Why are you giving the times in yrs? Don't you mean days? And I'd check those again.

Wow. Don't I feel silly. I was working on several problems at once and I guess I forgot this one was in days, not years and it worked. Good eye! Also, Thanks a ton!
 

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