Differential Equations and Circuits

Click For Summary
Understanding the arrangement of variables in differential equations for LR circuits is crucial for proper integration. In the equation L(dI/dt) + RI = V, the terms must be organized to maintain the relationships between the variables during integration. The variable I is grouped with dI because they both change together, while V must remain with IR to ensure the integrity of the equation. The placement of L, V, and R can vary depending on whether they are constants or functions of time, which affects how they are treated in the integration process. Properly arranging these terms is essential for accurate results in solving circuit equations.
nikki__10234
Messages
3
Reaction score
0
So, I'm learning how to solve LR, RC, LC etc. types of circuits using differential equations. I understand how to do the math with differential equations, but I am confused as to why the variables are split in the way they are.

For example, for an LR circuit you have the equation
L(dI/dt)+RI=V

and then the book integrates both sides:
∫(dI/(V-IR))=∫(dt/L)
and so on...

It is justified to group the I term with the dI, but I don't understand why the L, V, and R terms are placed as they are? Could you get the same result if they were not arranged in this way since the integral is not being taken in terms of V, R or L?
 
Physics news on Phys.org
welcome to pf!

hi nikki! welcome to pf! :smile:
nikki__10234 said:
L(dI/dt)+RI=V

and then the book integrates both sides:
∫(dI/(V-IR))=∫(dt/L)
and so on...

It is justified to group the I term with the dI, but I don't understand why the L, V, and R terms are placed as they are? Could you get the same result if they were not arranged in this way since the integral is not being taken in terms of V, R or L?

the V has to stay with the IR …

can you see any way of getting the IR over onto the LHS (with the dI), without the V coming with it?​

but the L could go either side
 
nikki__10234 said:
So, I'm learning how to solve LR, RC, LC etc. types of circuits using differential equations. I understand how to do the math with differential equations, but I am confused as to why the variables are split in the way they are.

For example, for an LR circuit you have the equation
L(dI/dt)+RI=V

and then the book integrates both sides:
∫(dI/(V-IR))=∫(dt/L)
and so on...

It is justified to group the I term with the dI, but I don't understand why the L, V, and R terms are placed as they are? Could you get the same result if they were not arranged in this way since the integral is not being taken in terms of V, R or L?
The only requirement is that any variables which actually vary in the range of integration stay inside an integral, but it will help if it varies as a function of the variable of integration with which it is placed.
E.g. if L = L(t) then it would best be placed in the integral .dt as above, whereas if R is a constant then you could just as easily write
∫(dI/(V/R-I))=R∫(dt/L)
OTOH, if V = V(t) it's going to get tricky ;-).
 
Topic about reference frames, center of rotation, postion of origin etc Comoving ref. frame is frame that is attached to moving object, does that mean, in that frame translation and rotation of object is zero, because origin and axes(x,y,z) are fixed to object? Is it same if you place origin of frame at object center of mass or at object tail? What type of comoving frame exist? What is lab frame? If we talk about center of rotation do we always need to specified from what frame we observe?

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 2 ·
Replies
2
Views
1K