Differential Equations and Substitutions (Calc 2)

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Homework Help Overview

The problem involves solving the differential equation xy' = y + xe^(y/x) using the substitution v = (y/x). Participants are exploring the implications of this substitution in the context of differential equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to express dy/dx in terms of x and v, and some question how to derive dy/dx from the substitution. There is uncertainty about the relationship between v and its derivatives.

Discussion Status

The discussion is ongoing, with participants providing guidance on the necessary changes of variables and derivatives. There is recognition of the complexity introduced by the substitution, and multiple interpretations of how to proceed are being explored.

Contextual Notes

Some participants express confusion regarding the derivatives and the relationship between v and x, indicating that additional clarification may be needed to fully understand the substitution process.

lelandsthename
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Homework Statement


Solve xy' = y + xe^(y/x) using the substitution v=(y/x)


Homework Equations


Solving differential equations, substitution


The Attempt at a Solution


x (dy/dx) = y + xe^(y/x)

(dy/dx) = (y/x) + e^(y/x)

Substituting v=(y/x)

(dy/dx) = v + e^(v)

I do not know how to proceed from here. (There are so many variables that aren't x and y! Ahh) Any guidance would be greatly appreciated!
 
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You need to make the change of variable with the differential too. In other words you need to write

\frac{dy}{dx}

In terms of x and v. Note that v=v(x), that is, v is a function of x.
 
If v=y/x, then y= ??

and from that dy/dx= ??
 
Hmm, ok, so dv = dy/dx? Somehow I still think I'm missing something. Shouldn't there be a dv/dx somewhere or something? I am just not seeing it =/
 
lelandsthename said:
Hmm, ok, so dv = dy/dx? Somehow I still think I'm missing something. Shouldn't there be a dv/dx somewhere or something? I am just not seeing it =/
You're on the right lines, but not quite there. As Halls says,

y = v(x)\cdot x

Now you need to find the first derivative of the above function with respect to x,

\frac{dy}{dx} =\ldots
 

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