Differential equations assignment T2

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SUMMARY

The discussion focuses on solving a differential equation given by 2xy(dy/dx) = x² + 1, with a specific point (1, 2) through which the curve passes. The solution involves separating variables and integrating to find the general solution, which is (1/2)y² = (1/2)ln(x) + (1/4)x² + c. By substituting the point (1, 2) into the general solution, the constant c is determined to be 7/4, leading to the particular solution y = √[ln(x) + x²/2 + 3.5]. The calculations and logic presented are confirmed to be correct.

PREREQUISITES
  • Understanding of differential equations and their solutions
  • Familiarity with integration techniques, particularly integration by parts
  • Knowledge of logarithmic functions and their properties
  • Ability to manipulate algebraic expressions and solve for constants
NEXT STEPS
  • Study the method of separation of variables in differential equations
  • Learn about integration techniques, specifically integration by parts
  • Explore the applications of differential equations in real-world scenarios
  • Investigate the properties of logarithmic functions and their applications in calculus
USEFUL FOR

Students studying calculus, particularly those focusing on differential equations, as well as educators looking for examples of solving such equations. This discussion is also beneficial for anyone seeking to enhance their problem-solving skills in mathematics.

mathi85
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Hi!

I would like to ask anyone with some spare time to check my assignment questions. Last time I was asked to post one task at a time so I will.
Thank you in advance for your time.

Task 2:

Determine the equation of the curve which satisfies the differential equation:

2xy(dy/dx)=x2+1

and which passes through the point (1, 2)

Solution:

2xy(dy/dx)=x2+1 /:2x
y(dy/dx)=(x2+1)/(2x)
y(dy/dx)=(1/2)[(x2+1)/x]

∫ y dy=(1/2)∫ x+(1/x) dx
(1/2)y2=(1/2)(lnx+(1/2)x2)+c

General Solution
(1/2)y2=(1/2)lnx+(1/4)x2+c

x=1 when y=2

∴(1/2)(2)2=(1/2)ln(1)+(1/4)(1)2+c
∴c=7/4

Particular Solution:
(1/2)y2=(1/2)lnx+(1/4)x2+7/4
∴y=√[lnx+x2/2+3.5]
 
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