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Differential equations with laplace

  1. Aug 22, 2011 #1
    1. The problem statement, all variables and given/known data

    D^2 x -2x = 2sin2t x(0) = 0 , x'(0) = 1

    2. Relevant equations

    D^2 x = s^2ƒ[x] - sx(0) - x'(o)

    3. The attempt at a solution

    s^2ƒ[x] - sx(0) - x'(o) - 2ƒ[x] = 2sin2t

    s^2ƒ[x] - sx(0) - x'(o) - 2ƒ[x] = 4 / s^2 + 4

    ƒ[x] (s^2 + 1) + 1 = 4 / s^2 +4


    ƒ[x] (s^2 + 1) = 4 / s^2 +4 - 1/s

    i need help from here, i just keep messing up from this point and on, any help is greatly appreciated thanks !
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Aug 22, 2011 #2

    LCKurtz

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    Science Advisor
    Homework Helper
    Gold Member

    Perhaps, being careful with your arithmetic and parentheses you mean
    f[x](s2-2) -1 = 4/(s2+4)

    Your careless use of parentheses may be causing additional errors in your next steps, which you didn't show.
     
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