Differential Equations without numbers

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Homework Help Overview

The discussion revolves around a differential equations problem, specifically focusing on the relationships between functions A(c) and B(c) and their derivatives. Participants are exploring the steps involved in solving the equations without numerical values.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the process of solving for B(c) and its initial value B(0), with some expressing uncertainty about the requirements of the problem. There are attempts to clarify the integration process and the correct form of the differential equation being solved.

Discussion Status

The conversation includes various attempts to solve the problem, with some participants questioning their own reasoning and others providing feedback on integration methods. There is an acknowledgment of errors in the integration approach, leading to further clarification and attempts to correct the process.

Contextual Notes

Some participants express confusion about whether numerical solutions are expected, indicating a potential misunderstanding of the problem's requirements. There is also mention of an initial value problem (IVP) that is being used to find constants in the solution.

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Homework Statement


Here is the whole problem.
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Homework Equations


Not sure


The Attempt at a Solution


As you can see I got the first part. I solved the equation at part a.) for A(c) and plugged it into the D.E. and then solved for B(c). I need help on how to do the next part. How do I get B(0)?
 
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B(0)=A(0)-L, right?
 
I feel really dumb haha. Thank you, I was thinking they were looking for a number.
 
Now I'm having trouble with part b.

I'm solving dB/dc = -kB by doing it as a separable equation and getting B=sqrt(-2ck+2p) where p is the constant of integration. Then using the IVP of B to find P and plugging it back into the equation I got. Once I solve for B I put it in the equation at part a. and solving for A.
 
The square root is clearly NOT a solution. If [itex]B= \sqrt{2p- n2ck}= (2p- 2ck)^{1/2}[/itex] then [itex]dB/dc= (1/2)(-2k)(2p- 2ck)^{-1/2}= -k/B[/itex], not "-kB". Do the integration again.
 
And showing what you are integrating would be helpful as well.
 
I was integrating B dB when I should have been integrating 1/B dB

I got it, Thank you!
 

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