Differential Equations: Wronskian question.

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tarmon.gaidon
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Homework Statement


Hey Everyone,

Here is a problem from my book that has my confused. I really don't understand what it wants me to do so if anyone could give me a few hints it would be greatly appreciated.

I am doing problem 34, but I included 33 since it wanted to follow the same method.

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Sorry if I seem like I am asking you to do my homework. I'm not, just looking for a place to start.

Thanks,
Rob
 
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Mark44 said:
the attachment is invalid...

Really? I am able to open it just fine. Can anyone else open this?

EDIT: I take that back. It works for me in Chrome but not Firefox. I will upload it somewhere else and fix my post.
 
Hey office_Shredder,

I am reasonably familiar with using the Wronskian to show that functions are linearly independent. I am more used to this form:

8d606b824d0946483b111ce8935ba568.png


Where if W = 0 is true on an open interval I then the functions are linearly independent.

I don't completely understand the wronskian equation given in problem 33.
 
tarmon.gaidon said:
Hey office_Shredder,

I am reasonably familiar with using the Wronskian to show that functions are linearly independent. I am more used to this form:

8d606b824d0946483b111ce8935ba568.png


Where if W = 0 is true on an open interval I then the functions are linearly independent.

I don't completely understand the wronskian equation given in problem 33.

If you define [itex]f_i(x)=\text{exp}(r_i x)[/itex], [itex]1\leq i \leq n[/itex], what is [itex]f'_i(x)[/itex]? How about [itex]f''_i(x)[/itex]? What does that make the Wronskian for the [itex]n=3[/itex] case? Is there a rule for taking determinants where a column is multiplied by some factor that might help you here?
 
I understand where the matrix comes from now but I am not sure what method you are talking about for solving the determinant. Care to shed some light?
 
Use property 3 here. For example,

[tex]\begin{vmatrix} a & 2b & 3c \\ 4a & 5b & 6c \\ 7a & 8b &9c \end{vmatrix}=a\begin{vmatrix} 1 & 2b & 3c \\ 4 & 5b & 6c \\ 7 & 8b &9c \end{vmatrix}=ab\begin{vmatrix} 1 & 2 & 3c \\ 4 & 5 & 6c \\ 7 & 8 &9c \end{vmatrix}=abc\begin{vmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 &9 \end{vmatrix}[/tex]