Differential Geometry: Finding Integral Manifolds

  • Context: Graduate 
  • Thread starter Thread starter Sephi
  • Start date Start date
  • Tags Tags
    Integral Manifold
Click For Summary
SUMMARY

The discussion focuses on finding integral manifolds in differential geometry, specifically using the book "Intro to Smooth Manifolds" by John Lee. Integral manifolds are defined as manifolds M where, for every point p in M, there exists a linear map between the tangent space and the distribution at that point. A key resource mentioned is page 503 of the book, which discusses Frobenius' theorem and provides a technique for locating integral manifolds along with an illustrative example.

PREREQUISITES
  • Understanding of differential geometry concepts
  • Familiarity with tangent distributions
  • Knowledge of Frobenius' theorem
  • Experience with smooth manifolds
NEXT STEPS
  • Study Frobenius' theorem in detail
  • Explore examples of integral manifolds in differential geometry
  • Review tangent distributions and their properties
  • Read "Intro to Smooth Manifolds" by John Lee, focusing on pages 503 and beyond
USEFUL FOR

Students and researchers in mathematics, particularly those specializing in differential geometry and manifold theory.

Sephi
Messages
6
Reaction score
0
Hi people,
I'm learning differential geometry in a book (Intro to smooth manifolds, by John Lee) and I have some difficulties with the tangent distributions.
Actually, I don't know what to do if, given a distribution spanned by some vectors fields, I want to find its integral manifolds.
Can someone help me ?
 
Physics news on Phys.org
I either do not understand your question or I may be stating something that you already know...
Integral manifolds of a given distribution are all manifolds M for which \forall p \in M there is a linear map between the tangent space and the distribution at that point.
 
Have you read up to page 503? There, it is remarked that embedded in the proof of Frobenius' theorem is a technique for finding integral manifolds and an example illustrating the method is given.
 

Similar threads

  • · Replies 73 ·
3
Replies
73
Views
9K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
4K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K