Differentiate f(x)=arctan(e^5x)

[jpc90]

How do you differentiate f(x)=arctan(e^5x)

 

[dirk_mec1]

If it's w.r.t . x then use the chain rule e.g. u= e^(5x)

 

[jpc90]

I did something like,

1/1+(e^5x)^2

and then

5e^-5x/1+(e^10x)

I don't think that is right though, I'm pretty confused

 

[HallsofIvy]

How did you get e^-5x in the numerator? The derivative of e^5x is 5e^5x. That is what you should be multiplying by.

 

[jpc90]

I thought since e^5x is in the denominator that it is equal to e^-5x

 

[Jack_O]

You may find these sites useful:

differentiator: http://calc101.com/webMathematica/derivatives.jsp#topdoit"

Integrator: http://integrals.wolfram.com/index.jsp"
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According to the differentiator you should have got (e^5)/[(e^10)*(x^2)+1].

 

[jpc90]

ok thanks guys