Differentiating complex exponential

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SUMMARY

The discussion focuses on differentiating the function involving the complex exponential, specifically the expression sin(√3t + 1) transformed into Im[e^(√3t + 1)i]. The user multiplied this by e^t, resulting in Im[e^t * e^(√3t + 1)i]. The main question revolves around differentiating the term (t + √3ti + i) with respect to t, particularly how to handle the constant i. It is established that the derivative of i is zero, confirming that it does not contribute to the differentiation process.

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sozener1
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I asked to differentiate the given function using exponential function

with sin(√3t + 1) I turned it into Im[e^(√3t+1)i]

then I multiplied it by e^t

which gave Im[e^t*e^(√3t +1)i]

then I applied usual algebra to differentiate but I get a (t+√3ti +i) as the power of e

when I try to differentiate (t+√3ti +i) with respect to t I can do it with the first two terms but not i

how do you do differentiation over i? does it go to zero??
 

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sozener1 said:
I asked to differentiate the given function using exponential function

with sin(√3t + 1) I turned it into Im[e^(√3t+1)i]

then I multiplied it by e^t
Why? The original e^(√3t+1)i why not stay with that?

which gave Im[e^t*e^(√3t +1)i]

then I applied usual algebra to differentiate but I get a (t+√3ti +i) as the power of e

when I try to differentiate (t+√3ti +i) with respect to t I can do it with the first two terms but not i

how do you do differentiation over i? does it go to zero??
Yes, i is a constant. It's derivative is 0.
 
query

HallsofIvy said:
Why? The original e^(√3t+1)i why not stay with that? Yes, i is a constant. It's derivative is 0.

Just for assurance would you be able to get the derivative of order 8

with just e^(√3t+1)i ??

Cos the original function given was e^t*e^(√3t+1)i

as it was uploaded as an image file
 

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