Differentiating Complex Functions with Respect to x

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Differentiate with respect to x

dy = 3x^2 - 5√x + 1/2x^2
dx

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I don't understand how to differentiate this part: 5√x + 1/2x^2. I think changing it to indices form would be: x^1/5 + (2x)^-2?

How can it be worked out? :confused:
 
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[tex]5\sqrt{x}[/tex] is not [tex](x)^{\frac{1}{5}}[/tex]. It is five times [tex](x)^{\frac{1}{2}}[/tex].

The last term is a bit ambiguous, the way you've typed it. Is it [tex]\frac{1}{2}x^2[/tex] or [tex]\frac{1}{2x^2}[/tex]? Anyway, neither cannot be simplified to (2x)^-2.
 
neutrino said:
[tex]5\sqrt{x}[/tex] is not [tex](x)^{\frac{1}{5}}[/tex]. It is five times [tex](x)^{\frac{1}{2}}[/tex].

That makes more sense. :biggrin:

neutrino said:
The last term is a bit ambiguous, the way you've typed it. Is it [tex]\frac{1}{2}x^2[/tex] or [tex]\frac{1}{2x^2}[/tex]? Anyway, neither cannot be simplified to (2x)^-2.

It's [tex]\frac{1}{2x^2}[/tex]
 
Anived said:
It's [tex]\frac{1}{2x^2}[/tex]

It's then (1/2)(x^-2). (2x)^-2 would be (1/4)(x^-2).
 
neutrino said:
It's then (1/2)(x^-2). (2x)^-2 would be (1/4)(x^-2).

Ok. I understand. Thanks for the help. :biggrin: