How Do You Differentiate the Expression E^(xy) + y?

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Homework Help Overview

The discussion revolves around differentiating the expression E^(xy) + y, with participants exploring the implications of y being a function of x or a constant.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants question whether y is a function of x, with some suggesting that if y is constant, differentiation would be straightforward. Others indicate that y must be treated as a function of x, prompting the use of the product rule for differentiation.

Discussion Status

The discussion is active, with various interpretations being explored regarding the nature of y. Some participants have offered insights into the differentiation process, while others seek clarification on the problem's setup and notation.

Contextual Notes

There are indications of confusion regarding the notation used in the expression and the differential equation context, with requests for clearer parentheses to denote the exponent on e.

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Homework Statement




d/dx(E^xy+y)

Homework Equations





The Attempt at a Solution



How do you differentiate this phrase
 
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Well, is y a function of x? If not, it's a constant, and differentiating a constant is easy.
 
its a differential equation problem. show that

e^xy+y=x-1

is a solution to the de dy/dx=(e^-xy-y)/(e^-xy+X)
 
OK, so here y is a function of x, so you need to differentiate e^(xy) using the product rule. And the derivative of y is just y'.
 
how are you certain that y is a function of x?
 
or how can u tell, is what i mean
 
bmed90 said:
its a differential equation problem. show that

e^xy+y=x-1

is a solution to the de dy/dx=(e^-xy-y)/(e^-xy+X)

Please don't make us guess what the problem is. Use parentheses to indicate what the exponent on e is.

In the numerator, is it e-xy + x, or is it e-xy + x? Same question for the denominator.
 
Because dy/dx does not equal zero for all x. Therefore, y is not constant with respect to x, and therefore it is a function of x.
 
e^(-xy)+X same for bottom
 

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