Differentiation Map of a Complex Transformation

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Homework Help Overview

The discussion revolves around finding the eigenvectors and eigenvalues of the differentiation map from the vector space of differentiable functions C1(R) to itself. Participants are exploring the implications of this transformation in the context of differentiable functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand the nature of the differentiation map and its representation. Questions arise regarding the relationship between the derivative of functions and eigenvalues, particularly in the context of complex numbers versus real functions.

Discussion Status

Some participants are clarifying the definitions and implications of eigenvectors and eigenvalues in this context. There is acknowledgment of the differential equation f'(x) = λf(x) as a key aspect of the discussion. Guidance has been provided regarding the nature of eigenvalues and eigenvectors, but uncertainty remains among participants.

Contextual Notes

There is some confusion regarding the application of complex numbers in the context of C1(R), with a suggestion that the focus should be on differentiable real functions instead. The discussion includes the consideration of infinite eigenvalues and the form of associated eigenvectors.

nautolian
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Homework Statement



Find the eigenvectors and eigenvalues of the differentiation
map C1(R) -> C1(R) from the vector space of differentiable functions
to itself.

Homework Equations





The Attempt at a Solution



Hi, I'm not entirely sure how to go about this, because would the differentiation map of this be [(1,0),(0,1)] since its from it to itself? Thanks for the help in advance.
 
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hi nautolian! :smile:
nautolian said:
Find the eigenvectors and eigenvalues of the differentiation
map C1(R) -> C1(R) from the vector space of differentiable functions
to itself.

an eigenvector is an element f of C1(R) such that Df is a scalar times f :wink:
 
High, sorry I'm still not really sure where to go with this. I mean I understand that Df=(lambda)f, but in the terms of C^1(R) does this mean that the derivative of the complex number a+bi is the same as the eigenvalue times the vector? Sorry, I'm still somewhat lost. Thanks for your help though.
 
nautolian said:
High, sorry I'm still not really sure where to go with this. I mean I understand that Df=(lambda)f, but in the terms of C^1(R) does this mean that the derivative of the complex number a+bi is the same as the eigenvalue times the vector? Sorry, I'm still somewhat lost. Thanks for your help though.

I don't think this has anything to do with complex numbers. C^1(R) usually just means differentiable real functions. You need to solve the differential equation f'(x)=λf(x).
 
okay, would that mean that there are infinite eigenvalues with associated iegenvectors equal to A*exp(lambda*x)? where A is a constant? Sorry I'm still unclear about this. Thanks for the help though!
 
nautolian said:
okay, would that mean that there are infinite eigenvalues with associated iegenvectors equal to A*exp(lambda*x)? where A is a constant? Sorry I'm still unclear about this. Thanks for the help though!

Yes, that's it.
 

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