Is Every Differential 1-Form on a Line the Differential of Some Function?

Click For Summary

Homework Help Overview

The problem involves exploring whether every differential 1-form on a line can be expressed as the differential of some function, as presented in V.I. Arnold's Mathematics of Classical Mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the nature of differential 1-forms, with some suggesting that a general form is ##\omega = g(x) dx##. There is an attempt to connect this to the existence of a function ##G(x)## such that ##\omega = dG##.

Discussion Status

The discussion is ongoing, with participants questioning the original poster's understanding and emphasizing the need for integration to find the function. There is a clear indication that providing direct solutions is not permitted, which has been pointed out in the conversation.

Contextual Notes

Participants note the importance of adhering to forum rules regarding homework help, particularly the prohibition against providing complete solutions.

Abhishek11235
Messages
174
Reaction score
39

Homework Statement


This problem is from V.I Arnold's book Mathematics of Classical Mechanics.
Q) Show that every differential 1-form on line is differential of some function

Homework Equations


The differential of any function is
$$df_{x}(\psi): TM_{x} \rightarrow R$$

The Attempt at a Solution



The tangent to line is line itself. The differential 1-form is ##dy-dx=0##. Here I am struct. I don't know how to find out the differential. Can anyone help?
 

Attachments

  • Screenshot_2019-02-01-20-59-12.png
    Screenshot_2019-02-01-20-59-12.png
    37.5 KB · Views: 332
Physics news on Phys.org
Abhishek11235 said:
The tangent to line is line itself.
No.

Abhishek11235 said:
The differential 1-form is dy−dx=0dy−dx=0dy-dx=0.
No. A general differential 1-form is of the form ##\omega = g(x) dx##. You have to show that there exists a function ##G(x)## such that ##\omega = dG##.
 
Orodruin said:
No.No. A general differential 1-form is of the form ##\omega = g(x) dx##. You have to show that there exists a function ##G(x)## such that ##\omega = dG##.

That means I have to integrate. Can you provide me solution?
 
Abhishek11235 said:
Can you provide me solution?
That would violate the forum rules, which you would realize if you had bothered reading them.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 39 ·
2
Replies
39
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K