Differentiation using the quotient rule

[rikiki]

Homework Statement

Use the quotient rule to differentiate

y=(〖2x〗^4-3x)/(4x-1)

Homework Equations

y=(v du/dx-u dv/dx)/v^2

The Attempt at a Solution

Please also find attached attempt as jpeg for clarity, and textbook supplied answer.

dy/dx=([(4x-1).(8x^3-3)]-[〖(2x〗^4-3x).(4)])/((4x-1)^2 )

dy/dx=([(4).(8×3x^(3-1) )]-[(2×4x^(4-1)-3).(4)])/((4x-1)^2 )

dy/dx=((4).(24x^2 )-(8x^3-3).(4))/((4x-1)^2 )

I think i can take out the two 4's in the numerator, apart from this I'm not entirely sure where I've gone wrong. If anyone has any advice to get me back on track that would be great. Thanks.

 

[SteamKing]

In your first attempt, you had a massive algebra mistake in the numerator of the derivative. The second attempt appears to be OK.