- #1
jti5017
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Homework Statement
Determine whether x[n] is periodic, if so find the fundamental period.
ps forgive my notation, I'm new to physics forums and haven't had a chance to figure out the exact notation syntax yet.x[n]=cos(π/6 * n^2)
The Attempt at a Solution
x(n) is periodic when x(n) = x(n +N)x(n+N) = cos(π/6 * (n+N)^2)
π/6(2*n*N + N^2) = k*2*π
this is kinda where i got stuck
(2*n*N + N^2) = 12 * k