Difficult improper integral proof

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Homework Help Overview

The discussion revolves around proving the limit of an improper integral involving the exponential function, specifically \(\lim_{x \rightarrow \infty} \exp(-x^2) \int_0^x \exp(t^2) dt\). The subject area is calculus, focusing on limits and improper integrals.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts various methods, including bounding the expression, approximating the exponential function, and analyzing the behavior of the integral. Some participants suggest differentiating the function to simplify the limit, while others propose using l'Hôpital's rule, although there is uncertainty about its application.

Discussion Status

The discussion is ongoing, with participants exploring different approaches and questioning the applicability of certain techniques. There is no explicit consensus on the best method to proceed, and some participants express frustration over the lack of familiarity with l'Hôpital's rule.

Contextual Notes

Some participants note that they have not been taught l'Hôpital's rule, which influences their approach to the problem. There is also mention of difficulties with certain mathematical tools, such as hypergeometric functions, which complicate the discussion.

JG89
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Homework Statement


Prove that \lim_{x \rightarrow \infty} exp(-x^2) \int_0^x exp(t^2) dt = 0.


Homework Equations





The Attempt at a Solution



This question is giving me a lot of difficulty. I've tried a lot of different ways to do it, here is a list of ways that I've tried.

1) For t>= 1, we have 0 < exp(-x^2) \int_0^x exp(t^2) dt \le exp(-x^2) \int_0^x t e^(t^2) dt. Letting x tend to infinity, the right side of the inequality tends to 1/2 and so the expression which we wish to find the limit of is bounded and monotonically decreasing, thus it must converge.

2) I've tried approximating e^(t^2) by (1 + t^2/n)^n for large enough n, and then expanding using the binomial theorem and integrating term by term, giving me a polynomial of degree n + 1. We can then find a number m such that x^m > the polynomial in question for large enough x. Then we must find the limit of x^m/e^(x^2) as x tends to infinity. Using the theorem that e^(x^2) becomes infinite of a lower order of magnitude than x^m, we know that this quotient must tend to 0. I'm a bit sketchy about this one because I think m must tend to infinity with x, which complicates things. I think it's best to drop this idea.


3) I figured that the integral of t^(1/n) e^(t^2) for t>=1 decreases monotonically towards e^(t^2) for increasing n, and so if I can show that this integral divided by e^(x^2) tends to 0 for increasing x, then that proves what I want to prove. I've tried integrating it with Mathematica but it starts talking about hypergeometric functions, which I know nothing about so I don't think this is a good approach at all.


Any ideas?
 
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hi JG89

not 100% sure how or if this will work but if you let
f(x) = exp(-x^2) \int_0^x exp(t^2) dt

could you try differentiating f(x) and then re-integrating to obtain a simpler expression for your limit?
 
Nope. Just tried it, and differentiating and then integrating back again just gives me the same expression. I don't see much manipulation I can do to the derivative so that when I integrate I get a simpler expression back.
 
Your limit has the form 0*infinity. Doesn't that suggest using l'Hopital's rule?
 
L'Hospital works, but I've never been taught that, so I figure I should be able to do this question without it.
 
JG89 said:
L'Hospital works, but I've never been taught that, so I figure I should be able to do this question without it.

That's annoying.
 
I'm surprised that my calc book (Courant's book) makes no mention of l'hopital's rule. I guess there is no other way to do this then?
 
There almost certainly is. But I can't figure out a clever way to side step it right now. You could figure out why l'Hopital is true and then reverse engineer the proof into a specific proof for this problem. But that doesn't seem to be a good use of time. I'm surprised as well you don't have l'Hopital to apply yet. It's seems perfect for it.
 

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