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Difficult trignonometric Integral

  1. Nov 28, 2007 #1
    1. The problem statement, all variables and given/known data
    I need to find [tex]\int_{0}^{\pi}(sin(x)^{2n})dx[/tex].

    My idea was to write sine in the exponential definiton and use binomial theorem but i don´t really get anywhere :(

    Any suggestions ?
  2. jcsd
  3. Nov 28, 2007 #2


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    If you integrate by parts, you get a recursive formula for [tex] \int (sin(x)^{2n})dx[/tex] in terms of something like [tex]sin(x)^{2n-1}[/tex] by differentiating sin to the power of 2n-1, and integrating a sin. My guess is that'll do the trick
  4. Nov 28, 2007 #3
    hmm yea found that but i need an absolute formula if there even is one ?
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