Difficulty with optimization problems

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The discussion centers on challenges faced in solving optimization problems in calculus, particularly when trying to express a function in terms of a single variable. The user understands the general process of finding maxima and minima but struggles with the substitution step, specifically in a problem involving a cylinder inscribed in a sphere. They correctly identify the relationship between the cylinder's dimensions and the sphere's radius but fail to derive the expected surface area result from their calculations. The user seeks clarification on how to properly substitute variables to reach the solution presented in their textbook. Understanding these substitution techniques is crucial for successfully solving optimization problems.
hexag1
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I'm going through a calculus textbook in an attempt to learn it myself. So far so good, but I've been stuck on optimization problems.
I understand the concept. The maxima and minima of a function can be found by looking at where its derivative = 0.
I also see that a function that has no upper or lower bound can still have local maxima and minima.
I went through the problems in max/min section of my textbook just fine.

But I have run into trouble in the optimization section.

In these problems, one is asked to maximize or minimize some value (say the volume of a box, or the area of a window, or whatever).
First, one writes a function, almost always of more than one variable.
Secondly, using other information, one finds an expression to substitute into the function and write it in terms of a single variable.
Third, one differentiates the function, looks for the zeroes, and then evaluates the initial function at these values etc.

My problem is in step two. I can't find ways of writing functions in terms of a single variable.
Here's one that gives me trouble:

A right circular cylinder is inscribed in a sphere of radius R. What is the maximum surface area of such a cylinder?

So, the cylinder is inside the sphere, its edges touching the sphere.
We can call its radius c, and its height h.

Its area is:

A = 2 \pi c^2 + 2 \pi c h


Now we have to differentiate and find A' . But how do we find a substitute for h?

From the cross section of the cylinder, we can see that the cylinder's radius and height/2 form a right triangle with the radius R of the sphere. So:

R^2 = c^2 + (h/2)^2 Right?

solving for h, we have:

h = 2 \sqrt {R^2 - c^2}

We then substitute h into the area function, and differentiate. I get nothing like what my textbook gives, which is \pi R^2(1+ \sqrt{5})

I don't see how they got this.
 
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hexag1 said:
I'm going through a calculus textbook in an attempt to learn it myself. So far so good, but I've been stuck on optimization problems.
I understand the concept. The maxima and minima of a function can be found by looking at where its derivative = 0.
I also see that a function that has no upper or lower bound can still have local maxima and minima.
I went through the problems in max/min section of my textbook just fine.

But I have run into trouble in the optimization section.

In these problems, one is asked to maximize or minimize some value (say the volume of a box, or the area of a window, or whatever).
First, one writes a function, almost always of more than one variable.
Secondly, using other information, one finds an expression to substitute into the function and write it in terms of a single variable.
Third, one differentiates the function, looks for the zeroes, and then evaluates the initial function at these values etc.

My problem is in step two. I can't find ways of writing functions in terms of a single variable.
Here's one that gives me trouble:

A right circular cylinder is inscribed in a sphere of radius R. What is the maximum surface area of such a cylinder?
R should be considered a constant.
hexag1 said:
So, the cylinder is inside the sphere, its edges touching the sphere.
We can call its radius c, and its height h.
I would call its radius r (which is different from R, the radius of the sphere).
You can simplify things by looking at a cross-section, so that you have a rectangle inscribed within a circle of radius R. The radius of the cylinder is one-half the width of the rectangle, and the height of the cylinder is the same as the height of the rectangle, or h.

The rectangle intersects the circle at the points (r, h/2), (r, -h/2), (-r, h/2), (-r, -h/2). I'm assuming the circle is centered at (0, 0). Since you know the equation of the circle (right?), you can get a relationship between r and h to eliminate one variable.
hexag1 said:
Its area is:

A = 2 \pi c^2 + 2 \pi c h


Now we have to differentiate and find A' . But how do we find a substitute for h?

From the cross section of the cylinder, we can see that the cylinder's radius and height/2 form a right triangle with the radius R of the sphere. So:

R^2 = c^2 + (h/2)^2 Right?

solving for h, we have:

h = 2 \sqrt {R^2 - c^2}

We then substitute h into the area function, and differentiate. I get nothing like what my textbook gives, which is \pi R^2(1+ \sqrt{5})

I don't see how they got this.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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