Diffraction due to a narrorw slit

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SUMMARY

The discussion centers on calculating the width of a narrow slit causing diffraction of light with a wavelength of 490 nm. Given the distance from the slit to the screen (3.6 m) and the distance between the central maximum and the third minimum (2 cm), participants emphasize using the single slit diffraction formula. This formula incorporates the slit width, wavelength, and the angular positions of the minima to derive the solution. The key takeaway is that the width of the slit can be determined by rearranging the diffraction equation based on the provided parameters.

PREREQUISITES
  • Understanding of single slit diffraction principles
  • Familiarity with the wavelength of light and its measurement
  • Knowledge of trigonometric functions, particularly sine
  • Ability to manipulate equations to solve for unknown variables
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  • Review the single slit diffraction formula and its derivation
  • Practice problems involving diffraction patterns and slit width calculations
  • Explore the effects of varying slit widths on diffraction patterns
  • Learn about experimental setups for measuring diffraction in a laboratory
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Students studying optics, physics educators, and anyone interested in understanding the principles of light diffraction and its practical applications.

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Homework Statement



Light of wavelength 490 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 3.6 m from the slit. The distance on the screen between the central maximum and the third minimum is 2 cm. What is the width of the slit?

Homework Equations





The Attempt at a Solution



Not sure where I need to start. Can someone help me out
 
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You should have in your notes or book, a formula ("single slit diffraction")for the angular positions of the various minima. This formula has the width of slit, the wavelength of the light, the number of the minimum counted from the centre, and the sin of the angle.
You can work out the angle from the distances given in the question, so you know all the quantities bar the width of the slit.
 

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