Diffraction Grating: 520nm & 630nm Wavelengths, 6000 Lines/cm, m=0-2 Fringes

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SUMMARY

This discussion focuses on the analysis of light diffraction through a grating with 6000 lines/cm for wavelengths of 520nm and 630nm. Participants are tasked with sketching the diffraction pattern from m=0 to m=2, calculating the angles for the first and second-order maxima, and determining the lowest value of m for which the 520nm line ceases to exist. The relevant formula for calculating the angles is sin(theta) = n * lambda / d, where d represents the slit separation. The discussion highlights the importance of understanding the relationship between wavelength and angle in diffraction patterns.

PREREQUISITES
  • Understanding of diffraction grating principles
  • Familiarity with the formula sin(theta) = n * lambda / d
  • Knowledge of light wavelengths and their behavior in optics
  • Ability to interpret and sketch diffraction patterns
NEXT STEPS
  • Study the principles of diffraction grating and its applications in optics
  • Learn how to calculate diffraction angles for various wavelengths using the formula sin(theta) = n * lambda / d
  • Explore the concept of maxima and minima in diffraction patterns
  • Research the limitations of diffraction, specifically when sin(theta) exceeds 1
USEFUL FOR

Students and educators in physics, optical engineers, and anyone interested in the practical applications of diffraction grating in analyzing light wavelengths.

rojasharma
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light wavelengths of 520nm and 630nm passes through a diffraction grating that contains 6000lines/cm. a) sketch a diagram of the image produced from m=0 to m=2. label the order of each fringe.b) calculate the angles for the first and second-order maxima that would appear on the screen. c) What is the lowest value of m for which the 520-nm line no longer exists? I have no idea how to do this question:(..
 
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i still don;t get it :(
 
rojasharma said:
i still don;t get it :(
you have all the data u want...
For (1) , there is a central maximum at theta =0 where the two rays coincide...
and the greater the wavelength , the greater the theta the ray is for the same order...
(sin function is increasing between 0 to pi/2)
(2) sintheta = nlamda/d
you have the slit separation , lamda and n , so it is possible to calculate


c) No longer exist when sin theta >1
 
the picture will be similar to the one shown in the website?..do i need to use protractor for that?
 
rojasharma said:
the picture will be similar to the one shown in the website?..do i need to use protractor for that?
sketch... I don't think you need to do that:devil:
 
label the order of each fringe? what does this mean?
 
for part b) sintheta=mlmbda/d...do i use both wavelengths? or a difference of the wavelengths?...confused:S
 

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