Calculate Angles for Diffraction Grating 1st & 2nd Order Maxima

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SUMMARY

The discussion focuses on calculating the angles for the first and second order maxima of light passing through a diffraction grating with 6000 lines/cm. The relevant equation used is sin(Theta)m = m(Lambda)/d, where d is the distance between grating lines calculated as 1.667x10^-6 m. The first order maximum for the wavelength of 520 nm is calculated to be 22.2 degrees. A correction was noted regarding the use of the 630 nm wavelength instead of 520 nm for the calculations.

PREREQUISITES
  • Understanding of diffraction grating principles
  • Familiarity with the equation sin(Theta)m = m(Lambda)/d
  • Knowledge of wavelength measurements in nanometers
  • Ability to convert units from lines per centimeter to meters per line
NEXT STEPS
  • Calculate the angles for the second order maxima using both 520 nm and 630 nm wavelengths
  • Explore the impact of varying the number of lines in a diffraction grating on angle calculations
  • Investigate the effects of different wavelengths on diffraction patterns
  • Learn about the applications of diffraction gratings in spectroscopy
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding diffraction patterns and their calculations.

AClass
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Homework Statement



Light with wavelengths of 520 nm and 630nm passes through a diffraction grating that contains 6000 lines/cm.

1) calculate the angles for the first and second order maxima that would appear on the screen

Homework Equations



sin(Theta)m = m(Lamda)/d

The Attempt at a Solution



[6000 lines/cm]^-1 = 1.667x10-4 cm/line = 1.667x10-6 m/line

d=1.667x10-6 m

-light 1- m=1

sin(Theta)1=[(1)(5.20x10^-7m)]/[1.667x10-6m]
Theta 1 = 22.2 degrees

Am I on the right track? I just have to for the other 3 situations?
 
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AClass said:

Homework Equations



sin(Theta)m = m(Lamda)/d
That should be:
sin(Theta) = m(Lamda)/d​
No "m" on the left side of the equation. This makes no difference when m=1, but you'll get the wrong answer when m=2.

The Attempt at a Solution



[6000 lines/cm]^-1 = 1.667x10-4 cm/line = 1.667x10-6 m/line

d=1.667x10-6 m

-light 1- m=1

sin(Theta)1=[(1)(5.20x10^-7m)]/[1.667x10-6m]
Theta 1 = 22.2 degrees
It looks like you really used 630 nm, not 520 nm here.
Am I on the right track? I just have to for the other 3 situations?
You're close to the right track, see my comments above.
 

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