Diffraction Grating Relationship Question

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SUMMARY

The discussion focuses on the effects of changing the wavelength of light and the spacing between slits on the number of visible bright fringes in a diffraction grating setup. When the wavelength is doubled, the maximum order of bright fringes (m) is halved, resulting in a total of x+1 fringes on the screen. Conversely, if the slit spacing (d) is doubled, m doubles, leading to a total of 4x+1 fringes visible. These conclusions are derived from the application of Young's Slits equations.

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Homework Statement


A diffracting grating casts a pattern on a screen located a distance L from the grating. The central bright fringe falls directly in the center of the screen. For the highest-order bright fringe that hits the screen, m=x, and this fringe hits exactly on the screen edge. This means that 2x+1 bright fringers are visible on the screen. What happens to the number of bright fringes on the screen,

a). If the wavelnegth of the light passing through the grating is doubled
b). If the spacing d between adjacent slits is doubled

Homework Equations


Listed in attempt

The Attempt at a Solution


Using Young's Slits equations:
##\huge y_\text{bright}=\frac{\lambda L}{d}m \implies m=\frac{y_\text{bright}d}{\lambda L}##

a). m would halve
b). m would double

If someone could please check this, I would greatly appreciate it! I would also appreciate an explanation and steps to the right solution if this is wrong.

Thanks in advance!
 
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Or perhaps since..

# of fringes = 2x+1, where x=m, then 2m+1

a). if m halves, then # of fringes = x+1
b). if m doubles, then # of fringes = 4x + 1

Or maybe I'm just overthinking it?
 

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