Digital Clocks: Binomial Problem Analysis and Results

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SUMMARY

The discussion focuses on analyzing a binomial problem related to defective digital clocks produced by a company, where 5% of the clocks are defective. When randomly selecting 80 clocks, the expected number of defective clocks is calculated as 4. The probability of exactly 6 defective clocks is determined using the binomial distribution formula, specifically $\begin{pmatrix}80 \\ 6\end{pmatrix}(0.05)^6(0.95)^{74}$. Additionally, the probability of at least one defective clock is found by calculating the complement of the probability that none of the clocks are defective, which is $(0.95)^{80}$ subtracted from 1.

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A company makes digital clocks. It is determined that 5% of all clocks produced are defective.

you go to the warehouse and randomly select 80 clocks.
1. How many of the 80 clocks do you expect to be defective?

2.What is the probability that exactly 6 of the clocks are defective?

3. What is the probability that at least one of the clocks (out of 80) is defective? use the complement.
 
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Hi there,

Welcome to MHB! :)

We like to tackle one problem at a time. Which one do you want to look at? What are your thoughts on it?
 
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Math101_McF said:
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Ok so we really want to help you but won’t give you answers. If you show what you’ve done we will do a ton to get you to the finish line but if you want answers for free this isn’t the place.

What we do have here are volunteers with PhD’s, other advanced degrees, and years of experience teaching math. We actually want you to like math and learn. For free. Promise.
 
The answer is almost given in the question:
"A company makes digital clocks. It is determined that 5% of all clocks produced are defective.

you go to the warehouse and randomly select 80 clocks.
1. How many of the 80 clocks do you expect to be defective?"
5% of 80 is (0.05)(80)= 4.

"2. What is the probability exactly 6 clocks are defective."
Each clock is either "defective" or "not defective" so this is a "binomial distribution". There are 80 clocks. The probability any given clock is broken is 0.05 and the probability it isn't is 0.95. The probability exactly 6 out of 80 are broken is $\begin{pmatrix}80 \\ 6\end{pmatrix}(0.05)^6(0.95)^{74}$.

"3. What is the probability that at least one of the clocks (out of 80) is defective? use the complement."
The opposite of "at least one" is "none". Calculate the probability that none of the 80 clocks is defective, $(0.95)^{80}$ and subtract that from 1.
 
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