Dimension of the electric charge

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SUMMARY

The dimensions of electric charge can be expressed as kg^(1/2)*m^(3/2)/s in terms of mass (kg), length (m), and time (s). This conclusion is derived from the assumption that permittivity (epsilon zero) is dimensionless, leading to the relationship established by Coulomb's law, where q^2/r^2 equates to force. Additionally, references to Max Born's interpretation of Einstein's theory of relativity using the CGS system further support this dimensional analysis.

PREREQUISITES
  • Understanding of Coulomb's law
  • Familiarity with dimensional analysis
  • Knowledge of the CGS (centimeter-gram-second) system
  • Basic principles of electromagnetism
NEXT STEPS
  • Research the derivation of dimensions in electromagnetism
  • Explore the implications of permittivity in electric charge calculations
  • Study Max Born's contributions to relativity and electromagnetism
  • Learn about the applications of dimensional analysis in physics experiments
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Students of physics, researchers in electromagnetism, and anyone interested in the dimensional analysis of physical quantities will benefit from this discussion.

umut
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could someone told me an experiment that ı can find the dimensions of the electric charge in therms of m, kg, sec
the answer is kg^(1/2)*m^(3/2)/sn it can be found by assuming the epsilon zero is dimensionless
please say me an experiment that i can check it :confused: :confused:
 
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If permittivity is dimensionless, then from Coulomb's law, q^2/r^2 has dimensions of force. That's all you need to prove it.
 
Check out Max born's Einsteins's theory of relativity. He uses the cgs. system. e=cm(gm cm)^.5/sec. But what is the square root of a gram centimeter?
 
Hello Brian, welcome to Physics Forums.
Are you aware this thread is over 7 years old?

Resurrecting old threads without good reason is frowned on.
 
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