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- Thread starter Wledig
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RPinPA

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The log is dimensionless (arguments of logs, exponentials, trig functions should always be dimensionless). So the units of ##\partial{ln (\Omega)}/\partial{E}## are 1/energy.

Therefore the units of ##1/\beta## are energy, and those are the dimensions of ##kT##

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Thanks, I wasn't sure about what to do with the ln. Got intimidated, I guess.

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