Dipole in a Dielectric: Analysis of r→0

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SUMMARY

The discussion centers on the behavior of a dipole in a vacuum cavity within an infinite Lithium Hydroxide (LiOH) dielectric. The potential is given by Vin = Arcos(theta) + B/(r^2) * cos(theta) and Vout = C/(r^2) * cos(theta). As r approaches 0, the electric field does not converge to a dipole field due to the presence of the term Acos(theta). However, the differentiation order does not affect the outcome, and the condition serves to determine the coefficient B, indicating that the dipole field dominates as r approaches zero.

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  • Basic concepts of dielectric materials, specifically Lithium Hydroxide (LiOH)
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sachi
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We have a dipole in a vacuum cavity inside an otherwise infinite LIH dielectric.
We assume form Vin = Arcos(theta) + B/(r^2) * cos(theta)
Vout = C/(r^2) * cos(theta)
We are told that "as r tends to 0 the field must approach the dipole field".
I'm not sure if they are talking about the E-field or the potential, as the E-field does not appear to tend to a dipole field as r tends to zero (if you differentiate Vin wrt r to get the E-field, you find a term Acos(theta) which does not tend to zero as r tends to zero. therefore we don't get a purely dipole type field. is it legitimate to let r tend to zero first, then perform the differentiation to get the E-field, or are they just talking about the potential anyway in the first place?)

thanks for your help
 
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The order of differentiation doesn't matter. Remember that the dipole part blows up at r = 0 so the constant term gets completely swamped, that's what they mean when they say the field approaches the pure dipole field. The purpose of this condition is simply to tell you what the coeffecient B is.
 

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