Dirac Delta from Continous Eigenfunctions

Click For Summary

Discussion Overview

The discussion revolves around the mathematical properties of the Dirac delta function in the context of continuous eigenfunctions of an operator with a continuous spectrum. Participants explore the implications of the Dirac delta function in relation to inner products of eigenfunctions and the coefficients of these functions.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions the origin of the Dirac delta function in the equation for determining coefficients of eigenfunctions, particularly why it must be infinite when the eigenfunctions are equal.
  • Another participant draws a parallel between this discussion and a previous one involving discrete eigenfunctions, suggesting that the relation must hold for arbitrary coefficients, leading to the necessity of the Dirac delta function.
  • A different participant specifically inquires about the requirement for the inner product of eigenfunctions to be infinite when the functions are the same.
  • Another contribution references the definition of the Dirac delta function and its properties, emphasizing the integral of the delta function over its domain.
  • One participant expresses a desire to understand why the integral of the eigenfunctions results in infinity when the functions are identical.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the necessity of the Dirac delta function's properties, particularly the condition of infinity for equal eigenfunctions. Multiple viewpoints are presented, and the discussion remains unresolved.

Contextual Notes

There are limitations in the understanding of the mathematical implications of the Dirac delta function and its role in the context of continuous eigenfunctions, particularly regarding the assumptions made about the inner products and the nature of the integrals involved.

Master J
Messages
219
Reaction score
0
In the equation for determining the coefficients of eigenfunctions of a continuous spectrum operator, I have trouble understanding the origin of the Dirac delta.

a_f = INTEGRAL a_g ( INTEGRAL F_f F_g ) dq dg

a is the coefficient, F = F(q) is an eigenfunction.

From this it is shown that the first integral (ie. of the eigenfunctions with dq) must be a Dirac delta function, that is, that for f = g it is infinite. Why is this? Landau Lifgarbagez states that it is to prevent the integral with dg from vanishing, but I don't see this.

This would mean that a_f = INTEGRAL a_f (infinity) df ...how is this?


Cheer folks! :)
 
Physics news on Phys.org
This is pretty much the same question as before, right? Only last time it was discrete (Eq 3.5) an = Σ am ∫ ψm ψn* dq, and this time it's continuous (Eq 5.3) af = ∫ af' (∫ψf'ψf* dq) df'.

In both cases, the reason is (like LL say): "This relation must hold for arbitrary af". The only way an = Σ am (...blah...) can hold for arbitrary an is if (...blah...) is a Kronecker delta, δmn, and the only way af = ∫ af' (...blah...) df' can hold for arbitrary af is if (...blah...) is a delta function, δ(f-f').
 
That's all good, but it's specifically the infinity part...why must the inner product of the two eigenfunctions when f=g inner product of it with itself) be infinity to satisfy this??
 
I can't see what those equation are. But let me say something.

Even though
δ(x)={infinity; x=0}={0; x≠0}

But from the definition:
∫δ(x)dx=1 -----> The area under the 'curve' must be 1:
Dirac_function_approximation.gif

The Dirac delta function as the limit (in the sense of distributions) of the sequence of Gaussians: Wiki

so, for every single function, there must be a value a that satisfy the equations:
f(a)=∫f(x-a)δ(x)dx
 
[itex]\int[/itex] [itex]\Psi[/itex] [itex]_{f}[/itex] [itex]\Psi[/itex] [itex]_{g}[/itex] dqThought I might as well get used to this Latex thing :D

My question is, why is this integral infinity when f=g ?

Psi is an eigenfunction of a continuous spectrum operator
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 2 ·
Replies
2
Views
22K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K