Representation of Dirac-delta function

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SUMMARY

The discussion focuses on demonstrating that the function \(\delta_\epsilon(x) = \frac{\epsilon}{\pi (x^2 + \epsilon^2)}\) serves as a representation of the Dirac delta function. Key properties established include the limit \(\lim_{\substack{\epsilon \to 0}} \delta_\epsilon(x) = 0\) and the integral \(\int_{-\infty}^{\infty} \delta_\epsilon(x) dx = 1\). The third requirement, \(\lim_{\substack{\epsilon \to 0}} \int_{-\infty}^{\infty} f(x) \delta_\epsilon(x) dx = f(0)\), is derived using the mean value theorem, which allows the extraction of \(f(c\epsilon)\) from the integral. The discussion also suggests exploring the Cauchy residue theorem as an alternative method for evaluating the limit.

PREREQUISITES
  • Understanding of Dirac delta function properties
  • Familiarity with the mean value theorem for integrals
  • Knowledge of Cauchy residue theorem
  • Basic calculus, including limits and integrals
NEXT STEPS
  • Study the properties of the Dirac delta function in detail
  • Learn the mean value theorem for integrals and its applications
  • Explore the Cauchy residue theorem and its use in complex analysis
  • Practice evaluating limits involving parameterized integrals
USEFUL FOR

Students and educators in mathematics, particularly those studying analysis and functional analysis, as well as physicists working with distributions and signal processing.

quantumkiko
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Homework Statement



Show that [tex]\delta_\epsilon(x) = \frac{\epsilon}{\pi (x^2 + \epsilon^2)}[/tex] is a representation of the Dirac delta function.

Homework Equations



I already know how the function can satisfy the first two requirements of being a dirac delta function, namely

[tex]\lim_{\substack{\epsilon \to 0}} \delta_\epsilon (x) = 0[/tex],
[tex]\int_{-\infty}^{\infty} \delta_\epsilon (x) dx = 1[/tex].

The third requirement is

[tex]\lim_{\substack{\epsilon \to 0}} \int_{-\infty}^{\infty} f(x) \delta_\epsilon (x) dx = f(0)[/tex].

The Attempt at a Solution



Following the previous examples of the book, it seems that the solution should be like this..

[tex]\frac{\epsilon}{\pi} \int_{-\infty}^{\infty} \frac{f(x)}{x^2 + \epsilon^2} dx<br /> = \frac{\epsilon}{\pi} \, f(c\epsilon) \int_{-\infty}^{\infty} \frac{1}{x^2 + \epsilon^2} dx <br /> = \frac{\epsilon}{\pi} \frac{\pi}{\epsilon} f(c\epsilon) = f(c\epsilon)[/tex]

where c varies from negative infinity to positive infinity. Now as we take the limit of epsilon to zero, we get f(0) which is the answer. But I don't get how the 2nd step (the one where the f(ce) came out of the integral) was done using the mean value theorem. I've looked up the integral forms of the mean value theorem but I still couldn't figure out how the 2nd line is done.
 
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How about applying the Cauchy residue theorem? This should yield a function of [tex]\varepsilon[/tex] which you can take the limit without a problem.
 

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