Representation of Dirac-delta function

In summary, the Dirac delta function can be represented by the function \delta_\epsilon(x) = \frac{\epsilon}{\pi (x^2 + \epsilon^2)} by satisfying the three requirements of a Dirac delta function. This includes taking the limit as \epsilon approaches 0 to satisfy the first two requirements, and using the mean value theorem or Cauchy residue theorem to show that the third requirement is also satisfied.
  • #1
quantumkiko
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Homework Statement



Show that [tex] \delta_\epsilon(x) = \frac{\epsilon}{\pi (x^2 + \epsilon^2)} [/tex] is a representation of the Dirac delta function.

Homework Equations



I already know how the function can satisfy the first two requirements of being a dirac delta function, namely

[tex] \lim_{\substack{\epsilon \to 0}} \delta_\epsilon (x) = 0 [/tex],
[tex] \int_{-\infty}^{\infty} \delta_\epsilon (x) dx = 1 [/tex].

The third requirement is

[tex] \lim_{\substack{\epsilon \to 0}} \int_{-\infty}^{\infty} f(x) \delta_\epsilon (x) dx = f(0) [/tex].

The Attempt at a Solution



Following the previous examples of the book, it seems that the solution should be like this..

[tex] \frac{\epsilon}{\pi} \int_{-\infty}^{\infty} \frac{f(x)}{x^2 + \epsilon^2} dx
= \frac{\epsilon}{\pi} \, f(c\epsilon) \int_{-\infty}^{\infty} \frac{1}{x^2 + \epsilon^2} dx
= \frac{\epsilon}{\pi} \frac{\pi}{\epsilon} f(c\epsilon) = f(c\epsilon)
[/tex]

where c varies from negative infinity to positive infinity. Now as we take the limit of epsilon to zero, we get f(0) which is the answer. But I don't get how the 2nd step (the one where the f(ce) came out of the integral) was done using the mean value theorem. I've looked up the integral forms of the mean value theorem but I still couldn't figure out how the 2nd line is done.
 
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  • #2
How about applying the Cauchy residue theorem? This should yield a function of [tex]\varepsilon[/tex] which you can take the limit without a problem.
 

FAQ: Representation of Dirac-delta function

What is the Dirac-delta function?

The Dirac-delta function, denoted as δ(x), is a mathematical function that is defined as having a value of 0 everywhere except at x = 0, where it has a value of infinity. It is often described as an infinitely tall and narrow spike centered at x = 0.

What is the purpose of the Dirac-delta function?

The Dirac-delta function is primarily used in mathematics and physics to model point masses or point charges. It is also used to simplify calculations in areas such as signal processing and quantum mechanics.

How is the Dirac-delta function represented mathematically?

The Dirac-delta function is typically represented using the following equation: δ(x) = 0 for x ≠ 0 and ∫δ(x)dx = 1. This means that the function has a value of 0 everywhere except at x = 0, where its integral over any interval containing 0 is equal to 1.

What are the properties of the Dirac-delta function?

Some key properties of the Dirac-delta function include: 1) δ(x) = δ(-x), meaning it is an even function; 2) δ(x) = 0 for x ≠ 0, meaning it is an odd function; 3) ∫f(x)δ(x)dx = f(0), where f(x) is any continuous function; and 4) δ(ax) = δ(x)/|a|, where a is a constant.

How is the Dirac-delta function used in practical applications?

The Dirac-delta function has many practical applications, such as in signal processing for representing impulses, in probability theory for representing point probabilities, and in quantum mechanics for describing wave functions. It is also used in solving differential equations and in Fourier analysis.

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