Direct Sum Proof Homework: Solve V = im(T) + ker(S)

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SUMMARY

The discussion focuses on proving that the vector space V can be expressed as the direct sum of the image of the linear transformation T and the kernel of the linear transformation S, denoted as V = im(T) + ker(S). The key conditions established are that im(T) ∩ ker(S) = {0} and im(T) + ker(S) = V. The user attempts to demonstrate these properties through algebraic manipulation, specifically using the relationships ST = 1v and TS = 1w, but encounters difficulties in completing the proof.

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Homework Statement


Here's the question... it was easier to format it in paint haha:
linalg.jpg


Please note I'll just write + to mean the plus with the circle around it (direct sum). + is just a normal addition.

Homework Equations





The Attempt at a Solution


V = im(T) + ker(S) means that im(T) ∩ ker(S) = {0} and that im(T) + ker(S) = V.

If ST = 1v, then TS = 1w. Thus w = T(v) and v = S(w).
S[w - TS(w)] = S(w) - STS(w) = v - ST(v) = v - S(w) = v -v = 0, therefore it's in ker(S).

Now I'm stuck. I don't know how to use this to do the proof... I think showing the intersection might go:
im(T) ∩ ker(S) = T(v) ∩ w - TS(w) = w ∩ 0 = 0. But I'm not sure.

I have no idea about the im(T) + ker(S) part though.
 
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Update: I'm thinking about using

w = (w - TS(w)) + TS(w).

Then w-TS(w) is in ker(S) and TS(w) is in im(T). Although I guess this is not really helpful because this doesn't show that it's equal to the space V...
 

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