B direction and magnitude of force on an arrow that left a bow.

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The angle between the direction of impact and the length of an arrow after it leaves a bow is typically small, with the arrow's trajectory being slightly upward and the impact angle slightly downward. This discrepancy arises from the physics of archery, where gravity affects the arrow's path. To minimize this angle, one can use a faster arrow by employing a stronger bow, lighter arrows, or advanced mechanisms like cams for increased thrust. Creative solutions such as active guidance or unique shooting environments could also be explored. Understanding these dynamics can enhance accuracy in archery.
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TL;DR
what can the angle between the direction of force of impact and the length of the arrow be?
sir,
I would like to know what the angle formed between the direction of impact and the length of arrow that leaves a bow? If it exists can it be reduced?
thank you
 
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Usually direction of impact and direction of arrow motion coincide. Maybe I am not catching you.
 
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shivakumar said:
TL;DR Summary: what can the angle between the direction of force of impact and the length of the arrow be?

sir,
I would like to know what the angle formed between the direction of impact and the length of arrow that leaves a bow? If it exists can it be reduced?
thank you
Are you referring to the tension in the string of the bow?
 
shivakumar said:
I would like to know what the angle formed between the direction of impact and the length of arrow that leaves a bow? If it exists can it be reduced?
The direction of the arrow as it leaves the bow will usually be slightly upward. The direction of the arrow as it impacts the target will usually be slightly downward. That is why they call it archery.

If you want to reduce the discrepancy between the two angles, you want a faster arrow. Stronger bow, lighter arrow, shortened range, maybe cams to apply more thrust through the release, maybe a crossbow.

Or maybe get really creative with active guidance.

Or do your shooting on the vomit comet.
 
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