Direction of car's average acceleration vector as it turns

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Homework Help Overview

The discussion revolves around a car's average acceleration vector as it navigates a 90-degree turn, transitioning from an eastward to a southward direction while maintaining a constant speed. Participants explore the implications of this scenario within the context of physics, particularly focusing on vector analysis and directional conventions.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of average acceleration using vector differences and question the clarity of the original problem statement. There are inquiries about the appropriateness of compass headings versus Cartesian coordinates in expressing direction.

Discussion Status

The conversation is ongoing, with various interpretations of the direction of the average acceleration being explored. Some participants have provided guidance on the importance of using consistent directional terminology, while others have raised questions about the assumptions underlying the problem setup.

Contextual Notes

There is mention of conventions regarding angle measurement from the positive x-axis and the potential for different interpretations based on the coordinate system used. Participants note the importance of clarity in communication, especially in an academic context.

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Homework Statement



A car, initially going east ward, rounds a 90 degree curve and ends up heading southward. If the speedometer reading remains constant, what's the direction of the car's average acceleration.



The Attempt at a Solution



a = Δv/Δt

vi = (c,0)
vf = (0,-c)

(vf - vi )/Δt =(-c,-c)/Δt
 
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negation said:

Homework Statement



A car, initially going east ward, rounds a 90 degree curve and ends up heading southward. If the speedometer reading remains constant, what's the direction of the car's average acceleration.



The Attempt at a Solution



a = Δv/Δt

vi = (c,0)
vf = (0,-c)

(vf - vi )/Δt =(-c,-c)/Δt
Is there a question here? This result looks correct. If they are asking for the direction, it's SW.
 
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Technically the answer should be given in terms of compass headings.
I agree a question would be nice, then we don't have to guess the issue.

Is it reasonable to guess that time into the corner is equal to time out of the corner?
 
Simon Bridge said:
Technically the answer should be given in terms of compass headings.
I agree a question would be nice, then we don't have to guess the issue.

Is it reasonable to guess that time into the corner is equal to time out of the corner?

My answer tallies with the book except that instead of SW, I chose my answer in the form of Cartesian coordinate-much more empirical and non-arbitrary to me.

So relative to the East and using the x-axis as East direction, the car is 225°
 

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So relative to the East and using the x-axis as East direction, the car is 225°
... do you mean to ask if this is correct?

Do you mean 225deg clockwise or anticlockwise from East?

A compass bearing would be an angle measured clockwise from North, or it would be a name like "due N" or "NNE".

225deg clockwise from due E would be NW - a bearing of -45deg.

It is good practice to put the answer in the same terms that the question used ... so I'd pick "NW" rather than "-45deg" as the more appropriate of the two. It will make a difference to you marks in the coming years and to your employment prospects later.

Cartesian coordinate-much more empirical and non-arbitrary to me.
You seem to things it backwards:
Cartesian coords are arbitrary and non-empirical - compass directions are the result of empirical physical phenomena. This is proved from the fact you can draw cartesian axis in any orientation without much in the way of physical constraints but you don't get to pick the direction the north-seeking pole of the compass needle points.

Note: it helps us to help you if you ask questions: don't make us guess what you want.
 
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Simon Bridge said:
... do you mean to ask if this is correct?

Do you mean 225deg clockwise or anticlockwise from East?

A compass bearing would be an angle measured clockwise from North, or it would be a name like "due N" or "NNE".

225deg clockwise from due E would be NW - a bearing of -45deg.


You seem to things it backwards:
Cartesian coords are arbitrary and non-empirical - compass directions are the result of empirical physical phenomena. This is proved from the fact you can draw cartesian axis in any orientation without much in the way of physical constraints but you don't get to pick the direction the north-seeking pole of the compass needle points.

Note: it helps us to help you if you ask questions: don't make us guess what you want.

Sorry, I mis-typed it. It's 225° from the + x-axis.

That made sense.
 
Sorry, I mis-typed it. It's 225° from the + x-axis.
Yes. Is this angle clockwise or anticlockwise? When you give this kind of answer in an exam, you have to say.

If you gave the compass direction, instead, it would be clear.
Was my compass direction "NW" correct for the direction of the average acceleration?
 
Simon Bridge said:
Yes. Is this angle clockwise or anticlockwise? When you give this kind of answer in an exam, you have to say.

If you gave the compass direction, instead, it would be clear.
Was my compass direction "NW" correct for the direction of the average acceleration?

SW.
It's just strange that in Calculus class I didn't have to deal with the bearings. It would be implicitly assumed given that 225 is in the third quadrant and the convention was the +x-axis was the reference point.
 
Actually it is an arbitrary convention common to many calculus classes, that the angle is taken anticlockwise from the +x axis ... just like you commonly use the right-handed Cartesian coordinate system. But that's only a convention and it will not be the same everywhere. Even in calc, different coordinate systems will have different definitions ... spherical polar has two angles for instance.

Part of the question is testing to see if you can work with different conventions.
 

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