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## Homework Statement

A car, initially going eastward, rounds a 90 degree bend and ends up heading southward. If the speedometer reading remains constant, what is the direction of a car's average acceleration vector?

-So i know the speed remains constant.

## Homework Equations

average acceleration =( final velocity - initial velocity ) / elapsed time

## The Attempt at a Solution

initial velocity = vi + 0j

final velocity = 0i + -vj

average acceleration = (-vi + -vj) / elapsed time

I don't think that the time matters here, because the ratio of vj/vi will remain the same, so:

direction of motion = inverse tangent of (-vj/-vi) = 45 degrees.

I feel like the answer should be -45 degrees. Also the back of the book says average acceleration = 5.12 m/s

^{2}and that the angle should be 41 degrees south of west. How can they get an actual value for average acceleration? Any help would be greatly appreciated.