1. The problem statement, all variables and given/known data An electron moves with speed 4.00 105 m/s in a uniform magnetic field of 3.2 T, pointing south. At one instant, the electron experiences an upward magnetic force of 1.00 10-14 N. In what possible directions might the electron be moving at that instant? Give your answers as angles clockwise from south (from 0° to 360°), in increasing degrees. (I have to find two answers in degrees, both clockwise from south). 2. Relevant equations F = qvBsin(theta) 3. The attempt at a solution F = qvBsin(theta) sin(theta) = F / qvB = (1x10-14) / [(1.6x10-19)(4x105)(3.2)] = .0488 theta = sin-1(.0488) theta = 2.8 So my first angle was approximately 2.8. I subtracted that from 270 degrees ("south") to get my final angle of 267.2 degrees. Then I subtracted 2.8 from 180 to get my second angle, which was approximately 177.2. I subtracted THAT number from 270 degrees to get my final second angle of approximately 92.8 degrees. I thought that 267.2 and 92.8 were my answers, but they are coming up as incorrect. I also tried rounding to a whole number, which didn't work either.