Direction of the Electric Field

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Homework Help Overview

The discussion revolves around understanding the direction of the electric field in relation to the force experienced by a charge. Participants are exploring the principles of electric fields and forces, particularly in the context of charged particles and their interactions.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants are attempting to understand why the electric field is considered to point upwards based on the force acting on a charge. There are questions about the relationship between the charge of the particle and the direction of the electric field, as well as the effects of other charges on the field's direction.

Discussion Status

Some participants have offered insights into the nature of electric fields and forces, discussing how the direction of the electric field is determined by the charge type. There is an ongoing exploration of how external factors might influence the electric field direction, and multiple interpretations of the problem are being considered.

Contextual Notes

There are references to specific forces and the assumption that the charge in question is small, which may not significantly alter the existing electric field. The discussion also highlights the need for more specific conditions to draw definitive conclusions about the electric field's behavior.

Raybulous
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Homework Statement


a.jpg


Homework Equations


F = E x q

The Attempt at a Solution


I was told the direction of the E field should be pointing upwards but I have no clue as to why. I found the Force = 0.0012 N but not the direction.
 
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Hi, I am not sure if anybody had ever told you this, but if you take law of elementary charges e.g. like charges repel and opposite attracts; which is basically indicates the direction of the attraction or repulsion force is felt, And electric field is just the opposite of it which is again said as, q+ has E outwards and q- has inward electric field. Therefore, you can see that the negative q or electron is pulled or attracted to another charge by 0.0012N in the direction of F but as it's Electric field is drawn to it because it is a negative charge, so Electric field is actually pointing upward which is where you electron is.
 
jackMybrain@ru said:
Hi, I am not sure if anybody had ever told you this, but if you take law of elementary charges e.g. like charges repel and opposite attracts; which is basically indicates the direction of the attraction or repulsion force is felt, And electric field is just the opposite of it which is again said as, q+ has E outwards and q- has inward electric field. Therefore, you can see that the negative q or electron is pulled or attracted to another charge by 0.0012N in the direction of F but as it's Electric field is drawn to it because it is a negative charge, so Electric field is actually pointing upward which is where you electron is.
So to find the electric field direction we only have to look at the charge of the particle?
Hence the electric field is pointing towards the particle and not flowing in a constant direction?
 
It's flowing in a constant direction but it also changes depending on if there are any other sources e.g. outer electric field line exerted from a differently charged particle or if your charge particle is placed inside another electric field, which will change it's electric field direction. So, can't say directly unless you have made the question a bit more specific with condition. But for this case, it's safe to assume that Electric field is going upward by looking at the direction of the force and assuming that there is no repelling force by an unknown charge on the top y-axis.
 
Raybulous said:

Homework Statement


View attachment 87949

Homework Equations


F = E x q

The Attempt at a Solution


I was told the direction of the E field should be pointing upwards but I have no clue as to why. I found the Force = 0.0012 N but not the direction.
Look at the equation F=E*q. F and E are vectors, e is a scalar, it is negative now. What happens to the direction of a vector if you multiply it with a negative scalar? If the result, F, points downward, what is the direction of E?
 
Raybulous said:
So to find the electric field direction we only have to look at the charge of the particle?
Hence the electric field is pointing towards the particle and not flowing in a constant direction?
A charge does not feel its own electric field. When we say that a charged particle is placed in an electric field E, and a force acts on it, the force felt by the charge is F=qE, parallel or antiparallel with E, depending on the sign of the charge.
The net field will be modified by the added charge, but usually it is assumed that the charge is small and it disturbs the original field only very near to itself.
 

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