Direction of trajectory, system of DE's and portrait phase in plane phase

Click For Summary
SUMMARY

The discussion centers on solving a system of differential equations (DE's) represented as \(\alpha' = -2i \alpha\) and \(\beta' = 2i \beta\). The solution is expressed in terms of complex exponentials: \(\alpha(t) = c_1 e^{-2it}\) and \(\beta(t) = c_2 e^{2it}\). The eigenvalues are purely complex, indicating that trajectories in the phase plane are circular or elliptical around the origin (0,0). The user seeks clarification on determining the direction of rotation in the phase plane when dealing with complex values, particularly at the point (1,0).

PREREQUISITES
  • Understanding of differential equations (DE's)
  • Familiarity with eigenvalues and eigenvectors
  • Knowledge of phase plane analysis
  • Basic concepts of complex numbers and their geometric interpretation
NEXT STEPS
  • Study the properties of complex eigenvalues in differential equations
  • Learn about phase plane trajectories for systems with complex solutions
  • Explore the concept of orientability of the Jacobian and its implications
  • Investigate visualizing trajectories in higher-dimensional phase spaces
USEFUL FOR

Mathematicians, physicists, and engineering students focusing on dynamical systems, particularly those interested in the behavior of systems described by complex differential equations.

fluidistic
Gold Member
Messages
3,934
Reaction score
286
Hi guys!
I had the following system of DE's to solve:
\alpha '=-2i \alpha
\beta ' =2i \beta.
Where alpha and beta depend on t.
I solved it by writing the system under matricial form, found the eigenvalues and corresponding eigenvectors.
The solution is (and I've checked it, it works): \alpha (t)=c_1e^{-2it}, \beta (t) =c_2 e^{2it}.
Since the eigenvalues are purely complex the trajectories in the phase plane are either circles or ellipses around (0,0).
Now I've been reading http://tutorial.math.lamar.edu/Classes/DE/PhasePlane.aspx to check out how to determine the direction of rotation.
When I pick (\alpha , \beta ) =(1,0), I get that (\alpha ' , \beta ' )=(-2i ,0). However on the website I've just linked, there's no example of what happens when you get complex values. I don't know how to sketch the direction of the trajectory at the point (1,0) because of that complex number.
Is the direction counter clockwise, clockwise, none?!
 
Physics news on Phys.org
You appear to have a 4 dimensional phase space. How do you propose sketching trajectories in that in general?
OTOH, with beta initially zero, it will always be zero, so that makes it manageable.
 
Hey fluidistic.

Have you checked the orientability of the Jacobian (determinant)?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
12K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 4 ·
Replies
4
Views
20K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K