Solving a System of Coupled DEs: Eigenvalues & Trajectories

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SUMMARY

The discussion focuses on solving the second-order differential equation y'' + 5y' - 24y = 0 by converting it into a system of coupled first-order differential equations. The eigenvalues of the system are determined to be λ1 = -8 and λ2 = 3, indicating a saddle point at the origin due to the presence of real eigenvalues with opposite signs. The general solution is expressed as y(t) = αx(1)e^(-8t) + βx(2)e^(3t), where x(1) = [1; -8] and x(2) = [1; 3]. The discussion concludes with a need for further clarification on the nature of the critical point and trajectory sketching in the phase plane.

PREREQUISITES
  • Understanding of second-order differential equations
  • Familiarity with eigenvalues and eigenvectors
  • Knowledge of phase plane analysis
  • Basic skills in linear algebra
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  • Study the method of converting second-order DEs to first-order systems
  • Learn about phase plane trajectories and their significance
  • Explore the implications of eigenvalues on stability analysis
  • Review techniques for sketching trajectories in the phase plane
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Students and professionals in mathematics, engineering, and physics who are solving differential equations and analyzing their stability and behavior in phase space.

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Homework Statement



Express y'' + 5y' - 24y = 0 as a system of couple first order DEs, find the eigenvalues of the system and the nature of the critical point at the origin. As well as find the general solution to the system of coupled equations and sketch some trajectories in the phase plane.

Homework Equations





The Attempt at a Solution


I have no idea really where to start so this could be completely wrong..

Using y1 = y and y2 = y''
and (A-lambda I)x = 0

0 = \lambda2 + 5\lambda - 24
0 = (\lambda+8)(\lambda-3)
\lambda1 = -8, \lambda2 = 3

From \lambda1 = -8;
x(1) = [1; -8] (vector)

And from \lambda2 = 3;
x(2) = [1; 3]

So my general solution is y(t) = \alphax(1)e-8t + \betax(2)e3t

And from there I am stuck and not even sure if that is on the right path, let alone how to determine the nature of the critical point at the origin.. any ideas?
 
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Then using those results because I have two real eigenvalues of opposite signs does this mean with the nature of the critical point at the origin it is in fact a saddle point?
 

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