Discover the Single Solution for 3sinx - 1 = b in (0,2pi): Find the Value of b!

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SUMMARY

The equation 3sin(x) - 1 = b has exactly one solution in the interval (0, 2π) when b is a specific positive real number. To determine the value of b, one must analyze the intersections between the horizontal line y = b and the curve y = 3sin(x) - 1. The discussion emphasizes the importance of graphing these functions to visually identify the number of solutions, particularly focusing on the open interval (0, 2π).

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine.
  • Ability to graph equations and analyze intersections.
  • Familiarity with the concept of open intervals in mathematics.
  • Knowledge of solving equations involving trigonometric identities.
NEXT STEPS
  • Learn how to graph trigonometric functions using tools like Desmos or GeoGebra.
  • Study the properties of sine functions and their transformations.
  • Explore the concept of horizontal lines and their intersections with curves in calculus.
  • Investigate the implications of open versus closed intervals in mathematical analysis.
USEFUL FOR

Students studying trigonometry, educators teaching mathematical graphing techniques, and anyone interested in solving trigonometric equations within specified intervals.

TyErd
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the equation 3sinx - 1 = b, where b is a positive real number, has one solution in the interval (0,2pi). The value of b is:

Frankly I have no idea where to even start with this problem.
 
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Hi TyErd! :smile:

(have a pi: π :wink:)

Hint: how many solutions in (0,2π) does 3sinx - 1 = 15 have?

And 3sinx - 1 = 0.5 ? :wink:
 
Um. thnx for the pi. How do you know how many solutions there are?
 
TyErd said:
Um. thnx for the pi. How do you know how many solutions there are?

Draw a graph and find out.

Get on with it!
 
alright I've drawn the graph, so what parts of the graph do i have to look at to know how many solutions there?
 
hm..
 
Which parts? Umm...

If I asked you to find out how many solutions there are to x^2=10 how would you go about doing that by looking at a graph?
 
TyErd said:
alright I've drawn the graph, so what parts of the graph do i have to look at to know how many solutions there?
And you should be looking only at the part of the graph on the interval [0, 2π].
 
Nooo … (0,2π). :wink:
 
  • #10
tiny-tim said:
Nooo … (0,2π). :wink:
Right, tiny-tim. I missed that it was the open interval.
 
  • #11
so when it says solutions, should i be looking at the x intercepts?
 
  • #12
TyErd said:
alright I've drawn the graph, so what parts of the graph do i have to look at to know how many solutions there?

What is the graph that you have drawn? Specifically, what is the formula of the function you have graphed?
 
  • #13
I tried to draw 3sinx-1=15 by taking 15 onto the other side but I've just realized that isn't right. How do you graph an equation that equals a number?
 
  • #14
Graph 15=3sinx-1
Then graph y=15

Do you see how if you tried to solve these two equations simultaneously, you would get 15=3sinx-1?

Are there any intersections between the two functions?

Now, can you find any number b (such as 15) that makes it such that the equation 3sinx-1=b has only 1 real solution in the interval between 0 and 2π?
This is the same as saying for what number b will the function y=b intersect the function y=3sinx-1 only once in the interval (0,2\pi)?
 
  • #15
Thankyouuu! i get it finally, you made it so much easier. thnx
 

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