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Let [tex]\Sigma[/tex] = {[tex]\beta[/tex],x,y,z} where [tex]\beta[/tex] denotes a blank, so x[tex]\beta \neq[/tex] x, [tex]\beta \beta \neq \beta[/tex], and x[tex]\beta[/tex]y [tex]\neq[/tex] xy but x [tex]\lambda[/tex]y = xy.
Compute each of the following:
1: [tex]\parallel \lambda \parallel[/tex]
2: [tex]\parallel \lambda \lambda \parallel[/tex]
3: [tex]\parallel \beta \parallel[/tex]
4: [tex]\parallel \beta \beta \parallel[/tex]
5: [tex]\parallel \beta[/tex]3 [tex]\parallel[/tex]
6: [tex]\parallel[/tex] x [tex]\beta \beta[/tex] x [tex]\parallel[/tex]
7: [tex]\parallel \beta \lambda \parallel[/tex]
8: [tex]\parallel \lambda[/tex] 10 [tex]\parallel[/tex]
Uhm.. can someone help me out ?
I've tried like 3 days now (without progress). Discrete math sux :P
Compute each of the following:
1: [tex]\parallel \lambda \parallel[/tex]
2: [tex]\parallel \lambda \lambda \parallel[/tex]
3: [tex]\parallel \beta \parallel[/tex]
4: [tex]\parallel \beta \beta \parallel[/tex]
5: [tex]\parallel \beta[/tex]3 [tex]\parallel[/tex]
6: [tex]\parallel[/tex] x [tex]\beta \beta[/tex] x [tex]\parallel[/tex]
7: [tex]\parallel \beta \lambda \parallel[/tex]
8: [tex]\parallel \lambda[/tex] 10 [tex]\parallel[/tex]
Uhm.. can someone help me out ?
I've tried like 3 days now (without progress). Discrete math sux :P
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